Question: Figure shows two parallel loops of wire having a common axis. The smaller loop (radius r) is above the larger loop (radius R) by a
Figure shows two parallel loops of wire having a common axis. The smaller loop (radius r) is above the larger loop (radius R) by a distance x > R. Consequently, the magnetic field due to the counterclockwise current i in the larger loop is nearly uniform throughout the smaller loop. Suppose that x is increasing at the constant rate dx/dt = v.
(a) Find an expression for the magnetic flux through the area of the smaller loop as a function of x. In the smaller loop, find
(b) An expression for the induced emf and
(c) The direction of the induced current.

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a In the region of the smaller loop the magnetic field produced by the larger loop may be ... View full answer
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