Question: Find an equation for the plane through (- 2, 1, 5) that is perpendicular to the planes 4x - 2y + 2z = - 1

Find an equation for the plane through (- 2, 1, 5) that is perpendicular to the planes 4x - 2y + 2z = - 1 and 3x + 3y - 6z = 5.

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Normals to the two planes are 4 2 2 and 3 3 6 or simplifying n 1 2 1 1 ... View full answer

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