Question: Find the minimum value of (x, y) = (x 3)2 + (y 2)2 Starting at x = 1 and y = 1. Using

Find the minimum value of

ƒ(x, y) = (x – 3)2 + (y – 2)2

Starting at x = 1 and y = 1. Using the steepest descent method with a stopping criterion of εs = 1%. Explain your results.


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