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Q: From the MaxwellBoltzmann speed distribution, show that the most probable speed of a gas molecule is given by Equation 21.29. Note that the most probable

From the Maxwell–Boltzmann speed distribution, show that the most probable speed of a gas molecule is given by Equation 21.29. Note that the most probable speed corresponds to the point at which the slope of the speed distribution curve dNv / dv is zero.

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