From the natural abundance of ⁷⁹Br and ⁸¹Br, predict the relative amounts of CH⁷⁹Br₃, CH⁷⁹Br₂ ⁸¹Br, CH⁷⁹Br⁸¹Br₂, and CH⁸¹Br₃. As in Exercise 21-C, the fraction of each isotopic molecule comes from the expansion of (a = b)3, where a is the abun - dance of 79Br and b is the abundance of 81Br Note that (a + b)n =

Compare your answer with Figure 21-7

Figure 21-7

Exercise 21-C

Transcribed Image Text:

п(п — 1п - 2) n(n -1)-2b? + d-3b3 + .... a" – na"-'b + 2! 3!