Given the thermochemical equations Pb + Cl2 ( PbCl2H = 223 kJ PbCl2 + Cl2 ( PbCl4H
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Pb + Cl2 ( PbCl2ΔH = −223 kJ
PbCl2 + Cl2 ( PbCl4ΔH = −87 kJ determine ΔH for 2PbCl2 ( Pb + PbCl4
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