Question: Identical negative charges (Q = -e) are located at two of the three vertices of an equilateral triangle. The length of a side of the

Identical negative charges (Q = -e) are located at two of the three vertices of an equilateral triangle. The length of a side of the triangle is ℓ. What is the magnitude of the net electric field at the third vertex? If a third identical negative charge was located at the third vertex, then what would be the net electrostatic force on it due to the other two charges? Use symmetry and explain how you used it.

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