If D2 + aD + bl has distinct roots and , show that a particular solution is y = (ex ex) / (

If D2 + aD + bl has distinct roots µ and λ, show that a particular solution is y = (eµx – eλx) / (µ – λ). Obtain from this a solution xeλx by letting µ → λ and applying 1’Hopital’s rule.