Question: If p X (k) = (10/k)(0.7) k (0.3) 10k , k = 0, 1, . . . , 10, is it appropriate to approximate P(4

If pX(k) = (10/k)(0.7)k(0.3)10−k, k = 0, 1, . . . , 10, is it appropriate to approximate P(4 ≤ X ≤ 8) by computing the following?

3.5 10(0.7) 10(0.7) (0.3) 8.5 10(0.7)

Explain.

3.5 10(0.7) 10(0.7) (0.3) 8.5 10(0.7)

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