Question: If the independent r.v.s Xj, j ¥ 1, are distributed as U (-j, j), then show that the Lindeberg condition (see relation (12.24)) holds, so

If the independent r.v.s Xj, j ‰¥ 1, are distributed as U (-j, j), then show that the Lindeberg condition (see relation (12.24)) holds, so that

N (0, 1), L() = Sn'n00

Where

If the independent r.v.s Xj, j ‰¥ 1, are distributed

Recall that X ~ U(α, β) means that the r.v. X has the uniform distribution with parameters α and β (α < β), its probability density function is p(x) =

If the independent r.v.s Xj, j ‰¥ 1, are distributed

Finally, recall that

If the independent r.v.s Xj, j ‰¥ 1, are distributed

n(n + l)(2n + l)/6.

N (0, 1), L() = Sn'n00

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X j U j j j 1 implies X j 0 2 j 2 X j j 2 3 so that s 2 n nn12n1 18 Also p j x 12 j for ... View full answer

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