If we were to write a chemical equation for the reaction of (2E,4E )-hexa-2,4-diene and methyl propenoate we might write it as shown below.
(a) Explain why we can predict that the endo and exo products will each be formed as a pair of enantiomers.
(b) What is the stereochemical relationship between either one of the endo enantiomers and either of the exo enantiomers?

Transcribed Image Text:

CH3 CH3 CH3 OCH3 OCH3 + OCH3 CHa O CH, o CH3 Major-by endo addition (plus enantiomer) Major-by exo addition (plus enantiomer)