Question: In each case find (if possible) conditions on a, b, and c such that the system has zero, one, or infinitely many solutions. (a) x
(a) x + 2y - 4z = 4
3a - y + 13z = 2
4x + y + a2z = a + 3
(b) x + y + 3z = a
ax + y + 5z = 4
x + ay + 4z = a
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b Hence x 3 s x 4 t are parameters and the equations give x 1 1... View full answer
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