Question: In each case, find the complex number z. (a) (i + z) - 3i(2 - z) = iz +1 (b) z2 = 3 - 4i

In each case, find the complex number z.
(a) (i + z) - 3i(2 - z) = iz +1
(b) z2 = 3 - 4i
(c) z(2 - i) = ( + 1)(1 + i)

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a iz 1 i z 6i 3iz 5i 1 3iz Hence 1 5i 1 2iz so b z 2 3 4i If z a bi the condition is a 2 b 2 2abi 3 ... View full answer

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