Question: In Exercises 1-3, solve the given system by back substitution. 1. x - 2y = 1 y = 3 2. 2u - 3v = 5

In Exercises 1-3, solve the given system by back substitution.
1. x - 2y = 1
y = 3
2. 2u - 3v = 5
2v = 6
3. x - y + z = 0
2y - z = 1
3z = - 1

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