Question: In Figure a, string 1 has a linear density of 3.00g/m, and string 2 has a linear density of 5.00g/m. They are under tension due

In Figure a, string 1 has a linear density of 3.00g/m, and string 2 has a linear density of 5.00g/m. They are under tension due to the hanging block of mass M = 500 g Calculate the wave speed on(a) String 1 and(b) String 2.Next the block is divided into two blocks (with M1 t Mz - M) and the apparatus is rearranged as shown in Figure b. Find(c) M1 and(d) M2 such that the wave speeds in the two strings are equal. String 1 String 2 Knot (a) String 1 String 2 M2 (b)

String 1 String 2 Knot (a) String 1 String 2 M2 (b)

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