Question: In Figure P3.66 a spider is resting after starting to spin its web. The gravitational force on the spider is 0.150 newton down. The spider

In Figure P3.66 a spider is resting after starting to spin its web. The gravitational force on the spider is 0.150 newton down. The spider is supported by different tension forces in the two strands above it, so that the resultant vector force on the spider is zero. The two strands are perpendicular to each other, so we have chosen the x and y directions to be along them. The tension Tx is 0.127 newton. Find (a) the tension Ty, (b) the angle the x axis makes with the horizontal, and (c) the angle the y axis makes with the horizontal.

In Figure P3.66 a spider is resting

Tx T.

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