Question: In Problems 1-4, find the particular solution. 1. y' = ex-3; y(0) = 2 2. y' = e2x+1; y(0) = e 3. dy = (1/x
1. y' = ex-3; y(0) = 2
2. y' = e2x+1; y(0) = e
3. dy = (1/x -x) dx; y(1) = 0
4. dy = (x2 - 1/x+1)dx; y(0) = 1/3
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