Question: In Problems 1-4, show that the given function is a solution to the differential equation. 1. y = x2; 4y - 2xy' = 0 2.
1. y = x2; 4y - 2xy' = 0
2. y = x3; 3y - xy' = 0
3. y = 3x2 + 1; 2y dx - x dy = 2 dx
4. y = 4x3 + 2; 3y dx - x dy = 6 dx
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1 2 3y xy 3x 3 x 3x 2 0 3 Thus 4 Substitute y ... View full answer
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