In Problems a-b, f"(x) is given. Find f (x) by antidifferentiating twice. Note that in this case your answer should involve two arbitrary constants, one from each antidifferentiation. For example, if f"(x) = x, then f'(x) = x2/2 + C1 and f (x) = x3/6 + C1x + C2. The constants C1 and C2 cannot be combined because C1x is not a constant.
a. f"(x) = 3x + 1
b. f"(x) = -2x + 3