Question: In Section 3.6 we found that the parametric form (x(t), y(t)) of the cubic Hermite polynomials through (x(0), y(0)) = (x 0 , y 0
In Section 3.6 we found that the parametric form (x(t), y(t)) of the cubic Hermite polynomials through (x(0), y(0)) = (x0, y0) and (x(1), y(1)) = (x1, y1) with guide points (x0+α0, y0+β0) and (x1−α1, y1−β1), respectively, are given by x(t) = (2(x0 − x1) + (α0 + α1))t3 + (3(x1 − x0) − α1 − 2α0)t2 + α0t + x0, And y(t) = (2(y0 − y1) + (β0 + β1))t3 + (3(y1 − y0) − β1 − 2β0)t2 + β0t + y0.
The Bézier cubic polynomials have the form x(t) = (2(x0 − x1) + 3(α0 + α1))t3 + (3(x1 − x0) − 3(α1 + 2α0))t2,+3α0t + x0 and y(t) = (2(y0 − y1) + 3(β0 + β1))t3 + (3(y1 − y0) − 3(β1 + 2β0))t2 + 3β0t + y0.
a. Show that the matrix

Transforms the Hermite polynomial coefficients into the Bézier polynomial coefficients
b. Determine a matrix B that transforms the Bézier polynomial coefficients into the Hermite polynomial coefficients.
0001 4630 4300 7600
Step by Step Solution
3.33 Rating (177 Votes )
There are 3 Steps involved in it
a We have b B A 1 7 6 0 ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
731-M-N-A-N-L-A (647).docx
120 KBs Word File
