Is (x1/m)n always equivalent to (xn)1/m? Try graphing Y1 = (x1/m)n and Y2 = (xn)1/m for various

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Is (x1/m)n always equivalent to (xn)1/m? Try graphing Y1 = (x1/m)n and Y2 = (xn)1/m for various integer values of m and n. Make sure you try positive and negative values for m and n, as well as different combinations of odd and even numbers. Check to see if the expressions are equal by inspecting the graphs and looking at table values for positive and negative values of x. Make observations about when output values are different and when output values do not exist. Make conjectures about the reasons for the occurrence of different values or no values?
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Discovering Advanced Algebra An Investigative Approach

ISBN: 978-1559539845

1st edition

Authors: Jerald Murdock, Ellen Kamischke, Eric Kamischke

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