Justify each step leading from Eqs. (3.10a) to (3.10d)? Aa pa = (aA) (ap) = a a
Question:
Aa̅ pa̅ = (Λa̅βAβ) (Λμa̅pμ)
= Λμa̅ Λa̅ βAβpμ,
= δμβAβpμ,
= Aβpβ.
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A a p a a b A b a p by Eq 27 and Eq 39 respectively a a b A ...View the full answer
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