Question: Let A be a square matrix. Prove that max {0, t} < p(A) < s, where s = max{s1,... , sn} is the maximal absolute

Let A be a square matrix. Prove that max {0, t} < p(A) < s, where s = max{s1,... , sn} is the maximal absolute row sum of A. as defined in (10.39), and t = min{|aij| - ri}. with ri given by (10.44).

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