Question: Let f(x) = 1/x-1. Then f(-2) = - 1/3 and f(2) = 1. Does the Intermediate Value Theorem imply the existence of a number c

Let f(x) = 1/x-1. Then f(-2) = - 1/3 and f(2) = 1. Does the Intermediate Value Theorem imply the existence of a number c between - 2 and 2 such that f(c) = 0? Explain.

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