Question: Let g : R R be defined by g(x) := x2sin (1/x2) for x 0, and g(0) := 0. Show that g is

Let g : R → R be defined by g(x) := x2sin (1/x2) for x ≠ 0, and g(0) := 0. Show that g is differentiable for all x ∈ R. Also show that the derivative gʹ is not bounded on the interval (-1, 1).

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