Let X be a normal random variable with mean 12 and variance 4. Find the value of
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Letting Z X 12 2 then Z is a standard normal Now 10 PZ c 12 2 But from Table 51 PZ 128 90 and so c 12 2 128 or c 1456 Table 51 X 01234567890 0 1 23456...View the full answer
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