Let xn+1 = (axn + c) mod m, where 2 < a < m, 0 < c
Question:
xn = (anx0 + c[(an - 1)/(a - 1)]) mod m, 0 < xn < m.
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Proof By Mathematical Induction For n 1 a n la n 1 a n1 a n2 1 ...View the full answer
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Related Book For 
Discrete and Combinatorial Mathematics An Applied Introduction
ISBN: 978-0201726343
5th edition
Authors: Ralph P. Grimaldi
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