Question: M = xi P (xi); x1 = 0, x2 = 1, x3 = 2, x4 = 3, x5 = 4, P (x1) = 0.240, P

M = Σxi P (xi); x1 = 0, x2 = 1, x3 = 2, x4 = 3, x5 = 4, P (x1) = 0.240, P (x2) = 0.412, P (x3) = 0.265, P (x4) = 0.076, P (x5) = 0.008 (mean of binomial distribution)

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