Question: Methanol (CH3OH) can be made by the controlled oxidation of methane: CH4(g) + 1/2O2(g) CH3OH(g) (a) Use data in Appendix C to calculate H

Methanol (CH3OH) can be made by the controlled oxidation of methane:
CH4(g) + 1/2O2(g) → CH3OH(g)
(a) Use data in Appendix C to calculate ΔH° and ΔS° for this reaction.
(b) How ΔG° is for the reaction expected to vary with increasing temperature?
(c) Calculate ΔG° at 298 K. Under standard conditions, is the reaction spontaneous at this temperature?
(d) Is there a temperature at which the reaction would be at equilibrium under standard conditions and that is low enough so that the compounds involved are likely to be stable?

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a H H f CH 3 OHg H f CH 4 g 1 2 H f O 2 g 2012 748 12 0 1264 kJ S S CH 3 OHg ... View full answer

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