Question: Near the point A (Fig. 3.10) lying on the boundary between glass and vacuum the electric field strength in Vacuum is equal to E0 =

Near the point A (Fig. 3.10) lying on the boundary between glass and vacuum the electric field strength in Vacuum is equal to E0 = 10.0 V/m, the angle between the vector E0 and the normal n of the boundary line being equal to a0 = 30°. Find the field strength E in glass near the point A, the angle θ between the vector E and n, as well as the surface density of the bound charges at the point A.

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