Question: Observer A sees two events at the same place (x = y = z = 0) and separated in time by t = 10-6 s.

Observer A sees two events at the same place (∆x = ∆y = ∆z = 0) and separated in time by ∆t = 10-6 s. A second observer B sees them to be separated by ∆t’ = 2 x 10-6s. What is the separation in space of the two events according to B? What is the speed of B relative to A?

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