Question: Obtain the Maclaurin series representation de+1 z cosh(z) = L 2n)l (1zl < 00). (2n)! n-0

Obtain the Maclaurin series representation
de+1 z cosh(z) = L 2n)l (1zl < 00). (2n)! n-0

de+1 z cosh(z) = L 2n)l (1zl < 00). (2n)! n-0

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