On a compact disc (CD), music is coded in a pattern of tiny pits arranged in a track that spirals outward toward the rim of the disc. As the disc spins inside a CD player, the track is scanned at a constant linear speed of v = 1.25 m/s. Because the radius of the track varies as it spirals outward, the angular speed of the disc must change as the CD is played. (See Exercise 9.22) Let's see what angular accc1cratim is required to keep v constant. T be equation of a spiral is r( 1/) = TO + f3II, where To is the radius of the spiral at 1/ = 0 and 13 is a constant. On a CD, TO is the inner radius of the spiral track. If we take the rotation direction of the CD to be positive, 13 must be positive so that r increases as the disc turns and 1/ increases.
(a) When the disc rotates through a small angle do, the distance scanned along the track is ds = r do. Using the above expression for T( 1/), integrate ds to find the total distance s scanned along the track as a function of the total angle 1/ through which the disc has rotated.
(b) Since the track is scanned at a constant linear speed v, the distance s found in part (a) is equal to vt. Use this to find 1/ as a function of time. There will be two solutions for 1/; choose the positive one, and explain why this is the solution to choose.
(c) Use your expression for I/ (t) to find the angular velocity w. and the angular acceleration a. as functions of time. Is a. constant? (d) On a CD, the inner radius of the track is 25.0 mm, the track radius increases by 1.55 #Lm per revolution, and the playing time is 74.0 min. Find the values of TO and 13, and find the total number of revolutions made during the playing time. (e) Using your results from parts (c) and (d), make graphs of w. (in rad/s) versus t and a. (m rad/s') versus t between t = 0 and t = 74.0min.