Question: Perform the same computation as in Sec. 24.3, but for the current as specified by i(t) = 5e-1.25t sin 2t for 0 t
i(t) = 5e-1.25t sin 2πt for 0 ≤ t ≤ T/2
i(t) = 0 for/ T/2 ≤ t ≤ T
Where T = I s. Use five-point Gauss quadrature to estimate the integral.
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