Question: Problem 49 suggests that if n is odd, then the nth order Maclaurin polynomial for sin x is also the (n + 1)st order polynomial,

Problem 49 suggests that if n is odd, then the nth order Maclaurin polynomial for sin x is also the (n + 1)st order polynomial, so the error can be calculated using Rn+1. Use this result to find how large n must be so that |Rn+1(x)| is less than 0.00005 for all x in the interval 0 ( x ( (/2. (n must be odd.)?

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Assume n is odd that is n 2m1 for m 0 Then R1 x R2m2 x f2m3 c 2m 3 x2m3 For all m ... View full answer

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