Question: A projectile is launched with speed Vo at an angle ao above the horizontal. The launch point is a height h above the ground. (a)
(a) Show that if air resistance is ignored, the horizontal distance that the projectile travels before striking the ground is Verify that if the launch point is at ground level so that h = 0, this is equal to the horizontal range R found in Example 3.8.
(b) For the case where Vo = 10 m/s and h = 5.0 m, graph x as a function of launch angle ao for values of ao from 0° to 90°. Your graph should show that x is zero if ao = 90°, but x is nonzero if ao = 0; explain why this is so.
(c) We saw in Example 3.8 that for a projectile that lands at the same height from which it is launched, the horizontal range is maximum for ao = 45°. For the case graphed in part (b), is the angle for maximum horizontal distance equal to, less than, or greater than 45°? (1hls is a general result for the situation where a projectile is launched from a point higher than where it lands.)
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IDENTIFY Apply Eq327 and solve for x SET UP The change in height is yh EXECUTE a We get a quadr... View full answer
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