Prove statement 6 of theorem A f(x) g(x) 1 M f(x) g(x) Lg(x) Lg(x) LM g(X) f(x) L L g(x) M curren g(x) f(x) L L g(X) M Now show that if Then there is a number Icirc acute 1 such that 0 lim g(x)M...

Suppose And f xgx LM gx f x L L gx M as shown in the text Choose 1 1 Si ...

Prove statement 6 of theorem A. |f(x) g(x) - 1.M = |f(x) g(x) - Lg(x) + Lg(x)

Question:

Prove statement 6 of theorem A.
|f(x) g(x) - 1.M = |f(x) g(x) - Lg(x) + Lg(x) - LM|
= |g(X) [f(x) - L] + L[g(x) - M]|
‰¤ |g(x) ||f(x) - L| + |L|| g(X) - M|
Now show that if

Then there is a number Î´1 such that
0

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Calculus

ISBN: 978-0131429246

9th edition

Authors: Dale Varberg, Edwin J. Purcell, Steven E. Rigdon

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Question Posted: Jun 21, 2016 09:37 AM

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Prove statement 6 of theorem A. |f(x) g(x) - 1.M = |f(x) g(x) - Lg(x) + Lg(x)

Question:

lim g(x)M

Step by Step Answer:

Suppose And f xgx LM gx f x L L gx M as shown in the text Choose 1 1 Si...View the full answer

Calculus

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