Prove the formula fm-1 (x)gn-1(x) [nf(x) g'(x) + mg(x) f'(x)] dx = fm(x) gn(x) + C
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∫ fm-1 (x)gn-1(x) [nf(x) g'(x) + mg(x) f'(x)] dx = fm(x) gn(x) + C
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