Recall Problem 5 1 15, where mechanical components have a width that is normally distributed with a mean u 2600 and a standard deviation 0 6 In an assembly procedure, four of these components need to be fitted side by side into a slot in another part (a) Suppose that the slots have a width of 10,40...

a Let the random variables X i be the widths of the component ...

Recall Problem 5.1.15, where mechanical components have a width that is normally distributed with a mean u

Question:

Recall Problem 5.1.15, where mechanical components have a width that is normally distributed with a mean u = 2600 and a standard deviation σ = 0.6. In an assembly procedure, four of these components need to be fitted side by side into a slot in another part.
(a) Suppose that the slots have a width of 10,402.5. What proportion of the time will four randomlv selected components be able to fit into a slot?
(b) More generally, suppose that the widths of the slots vary according to a normal with mean μ = 10,402.5 and standard deviation σ = 0.4. In this case, what proportion of the time will four randomly selected components be able to fit into a randomly selected slot?
Distribution
The word "distribution" has several meanings in the financial world, most of them pertaining to the payment of assets from a fund, account, or individual security to an investor or beneficiary. Retirement account distributions are among the most...