Question: Reconsider the paint-drying situation of Example 8.5, in which drying time for a test specimen is normally distributed with = 9. The hypotheses H0:
a. How many standard deviations (of ) below the null value is = 72.3?
b. If = 72.3, what is the conclusion using α = .002?
c. For the test procedure with α = .002, what is β(70)?
d. If the test procedure with α = .002 is used, what n is necessary to ensure that β(70) = .01?
e. If a level .01 test is used with n = 100, what is the probability of a type I error when μ = 76?
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a 723 7518 15 so 723 is 15 SDs of x below 75 b Pvalue PX 723 PZ 15 06... View full answer
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