Question: Reconsider the system defect situation described in Exercise 26 (Section 2.2). In Exercise 26 A certain system can experience three different types of defects. Let

Reconsider the system defect situation described in Exercise 26 (Section 2.2).
In Exercise 26
A certain system can experience three different types of defects. Let Ai (i = 1,2,3) denote the event that the system has a defect of type i. Suppose that
P(A1) = .12 P(A2) = .07 P(A3) = .05
P(A1 ⋃ A2) = .13 P(A1 ⋃ A3) = .14
P(A2 ⋃ A3) = .10 P(A1 ⋂ A2 ⋂ A3) = .01
a. Given that the system has a type 1 defect, what is the probability that it has a type 2 defect?
b. Given that the system has a type 1 defect, what is the probability that it has all three types of defects?
c. Given that the system has at least one type of defect, what is the probability that it has exactly one type of defect?
d. Given that the system has both of the first two types of defects, what is the probability that it does not have the third type of defect?

Step by Step Solution

3.43 Rating (172 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a 0612 50 The numerator comes from Exercise 26 b 0112 0833 The numerator ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

1172-M-S-P(10389).docx

120 KBs Word File

Students Have Also Explored These Related Statistics Questions!