Question: Refer to Exercise 10.87, comparing mean weight changes in anorexic girls for cognitive behavioral therapy and a control group. The MINITAB output shows results of
MINITAB output for comparing mean weight changes
.png)
T-Test of difference = 0(vs not =):
T-Value = 1.68 P-Value = 0.100 DF = 53
Both use Pooled StDev = 7.6369
a. Interpret the reported confidence interval.
b. Interpret the reported P-value.
c. What would be the P-value for Ha: μ1 > μ2? Interpret it.
d. What assumptions do these inferences make?
N MeanStDev SE Mean group cog behav 29 3.01 7.31 control Differen ce= mu (cog behav) -mu (control) Estimate for difference: 3.45690 95% CI for difference: (-0.68014, 7.59393) 1.4 1.6 26 0.45 7.99
Step by Step Solution
3.37 Rating (178 Votes )
There are 3 Steps involved in it
a We can be 95 confident that the population mean difference is between 07 ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
531-M-S-H-T (2741).docx
120 KBs Word File
