Question: Show that (a) (1 + i)i = exp (-/4 + 2n) exp (I ln 2/2) (n = 0, 1, 2, ...); (b) (1)1/ = e(2n+1)i
(a) (1 + i)i = exp (-π/4 + 2nπ) exp (I ln 2/2) (n = 0, ±1, ±2, ...);
(b) (−1)1/π = e(2n+1)i (n = 0,±1,±2, . . .).
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