Question: Show that ([A][B])T =[B]T [A]T by using bu b12 b13 [B] = b21 b22 b23 12 1 [A] = ). 0

Show that ([A][B])T =[B]T [A]T by using
bu b12 b13 [B] = b21 b22 b23 α12 α1μ [A] = α). α0

bu b12 b13 [B] = b21 b22 b23 12 1 [A] = ). 0

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