Question: Show that in Example 1 the absolute value of the error of x2 = 2.000/39.95 = 0.05006 is less than 0.00001.
Show that in Example 1 the absolute value of the error of x2 = 2.000/39.95 = 0.05006 is less than 0.00001.
Step by Step Solution
3.43 Rating (162 Votes )
There are 3 Steps involved in it
Since x 2x and 2 is exact x x ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
1-M-N-A-N-L-A (3).docx
120 KBs Word File
