Show that in Example 1 the absolute value of the error of x2 = 2.000/39.95 = 0.05006

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Show that in Example 1 the absolute value of the error of x2 = 2.000/39.95 = 0.05006 is less than 0.00001.

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Advanced Engineering Mathematics

ISBN: 978-0471488859

9th Edition

Authors: ERWIN KREYSZIG

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Question Posted: Nov 07, 2010 06:01 AM

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Show that in Example 1 the absolute value of the error of x2 = 2.000/39.95 = 0.05006

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Since x 2x and 2 is exact x x ...View the full answer

Advanced Engineering Mathematics

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