Question: Show that the linear transformation T is not surjective by finding an element of the codomain, v, such that there is no vector u with

Show that the linear transformation T is not surjective by finding an element of the codomain, v, such that there is no vector u with T (u) = v.
(E) | Г2а + 3b — с] 2b – 2c a - b+ 2c T: С + с, т

(E) | 2 + 3b ] 2b 2c a - b+ 2c T: + ,

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