Question: Show that the sum N1 + N2 + N3 + N4 is equal to 1 anywhere on a rectangular element, where N1 through N4 are

Show that the sum N1 + N2 + N3 + N4 is equal to 1 anywhere on a rectangular element, where N1 through N4 are defined by Eqs. (6.6.5).

In Eqs (6.6.5)

(b — х)(h — у) N2 4bh (b + x)(h – y) 4bh N1 (b + x)(h + y) 4bh (b – x)(h + y) N3 = N4 4bh ||

(b )(h ) N2 4bh (b + x)(h y) 4bh N1 (b + x)(h + y) 4bh (b x)(h + y) N3 = N4 4bh ||

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