Show that the sum N1 + N2 + N3 + N4 is equal to 1 anywhere on

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Show that the sum N1 + N2 + N3 + N4 is equal to 1 anywhere on a rectangular element, where N1 through N4 are defined by Eqs. (6.6.5).

In Eqs (6.6.5)

(b — х)(h — у) N2 4bh (b + x)(h – y) 4bh N1 (b + x)(h + y) 4bh (b – x)(h + y) N3 = N4 4bh ||

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A First Course in the Finite Element Method

ISBN: 978-1305635111

6th edition

Authors: Daryl L. Logan

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Question Posted: Feb 14, 2018 08:53 AM

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Show that the sum N1 + N2 + N3 + N4 is equal to 1 anywhere on

Question:

(b — х)(h — у) N2 4bh (b + x)(h – y) 4bh N1 (b + x)(h + y) 4bh (b – x)(h + y) N3 = N4 4bh ||

Step by Step Answer:

at center x 0 y 0 N 1 N 2 N 3 N 4 1 At point x ...View the full answer

A First Course in the Finite Element Method

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