Solve for n. 1. 4 n+1P2 = n+2P3 2. 5 n1P1 = nP2
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1. 4 · n+1P2 = n+2P3
2. 5 · n−1P1 = nP2
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1 4 n1 P 2 n2 P 3 Note n 1 for this to be defined 4n 1 n 1 n 2 n 1 4n 1 n n 2 n ...View the full answer
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