Question: Some numbers are not normally distributed. If the mean of the numbers is 38 and the standard deviation is 6, what proportion of values would

Some numbers are not normally distributed. If the mean of the numbers is 38 and the standard deviation is 6, what proportion of values would fall between 26 and 50? What proportion of values would fall between 14 and 62? Between what two values would 89% of the values fall?

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38 s 6 Between 26 and 50 x 1 50 38 12 x 2 26 38 12 2 2 k 2 ... View full answer

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