In a computation analogous to Examples 44. 9 and 44.12 of the text, find the relative homology

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In a computation analogous to Examples 44. 9 and 44.12 of the text, find the relative homology groups Hn( X, a) for the torus X with subcomplex a, as shown in Figs. 42.13 and Fig. 42.14.


Data from in Example 44.9

Let X be the simplicial complex consisting of the edges (excluding the inside) of the triangle in Fig. 44.10, and let Y be the subcomplex consisting of the edge P2P3. We have seen that H1(X) ≈ H1(S1) ≈ Z. Shrinking P2P3 to a point collapses the rim of the triangle, as shown in Fig. 44.11. The result is still topologically the same as S1. Thus, we would expect again to have H1(X, Y) ≈ Z. Generators for C1(X) are P1P2, P2P3, and P3P1. Since P2P3 ∈ C1(Y), we see that generators of C1(X)/C1(Y) are  P1P2 + C1(Y) and P3P1 + C1(Y). To find Z1( X, Y) we compute 


since P2, P3 ∈ C0(Y). Thus for a cycle, we must have m = n, so a generator of Z1(X, Y) is (P1P2 + P3P1) + C1(Y). Since B1(X, Y) = 0, we see that indeed H1(X, Y) ≈ Z. Since P1 + C0(Y) generates Z0(X, Y) and ∂1(P2P1 + C1(Y)) = (P1 - P2) + C0(Y) =P+ C0(Y), we see that H0(X, Y) = 0. This is characteristic of relative homology groups of dimension 0 for connected simplicial complexes.

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